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Two capacitors have capacitances of 6.5 pF and 40 pF. Initially, the first one has a potential difference of 17.0 V and the s
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1 C on 140.5 x 106 Solution Here - 6.54f (2=4 HF Net capacitance parallel, is citc2 10.5 4F gnitially charge c ,is -6 = 110.5

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