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12&13

12. Below figure mass of the disk is 3.0 kg.Three forces are applying on the object which they are cause to rotate the object
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720X03-70X03-50*0-2 D By Torque balance equations Z=12 ; Zz Torque forcex perpendiculco diptenee. In moment of Inertia of disNow abort mal Iz z miast m4 624 m3a2tb) = 4X0-16+ tox009 +48X0-25 c064 +0.9 +2 Is = 3.54kgn2 How about my - Iz=m162+ maal+ m2

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