Question

how do i solve for % error, by comparison with 1.602 x 10^-19?

1.6581x10-19 Data: Ministar (g): 19.5273, Mrinal (8): 19.16079 AM (g): 0.36669 I(A): 0,32 A t(s): 3600 Results: 1.6581 x 10-19 e (C/electron): %error, by comparison with 1.602 x 10-1°C: alom 63.55 с # of cu. (0.3666)(6.022x103) 3.4739 x 1021 # of transported e- 2x (3.4734 x 10") 6.9478x102 transported chrge (0.32A) (3600) 1152 1152 6.9478 x 1021

Answer 1

The formula for doing so is, $\text{relative error \%} = \frac{|\text{measured} - \text{actual}|}{\text{actual}}.$

So for your case, $\text{relative error \%} = \frac{1.6581 \times 10^{-19} - 1.602 \times 10^{-19} }{1.602 \times 10^{-19}} = \frac{1.6581 - 1.602}{1.602} = 0.0350187.$