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Problem 1 (3 points) Solve the following boundary value problem with the Galerkin method in which a three-term approximation,

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Answer #1

In this Galerkin method, the integral of the Residual function R, multiplied by a weighing function Wi is forced to be zero.

Every step by step procedure is explained in clear way in below images:

dof:- Given, ū(1) = C, 8, (+ ca da:(n) + Cz $3 (1) where, 8,cu) = (-X), 4.Cu) = -), %3() = 42C1->) du (0541) Boundary Conditi가기2 W 웃 C₂ x_x3 We By Galeskins Method, 0 { wir no fore . firy des is rans) - - c) inscust user) + leest) 모 2. - RC2 43 N +今 十 十 0 -QC, x3 十 十 3 i-exces) - - (42) -es(2-1 + ja - bus 学 - 学) Frey) - -- (一) (--) + tes) --G-s)。 - + so 会会员。 会+ > ~3C) +G=15 Ca C3 O) : , Cx) + p ) 15 Ds(x) + 9 —— The END

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