Question

All calculations need the counting processand Free Body Diagram.

3. Determine the maximum force P that can be applied without causing movement of the 300-lb crate that has a center of gravity at G. The coefficient of static friction at the floor is Is = 0.4. (20 Points) 1.5 ft 1.5 ft 2.5 ft P- 'T 4.5 ft 3.5 ft

Answer 1

Giveno Free body diagram Mg -0.4', 1.5 1-5 tha G 4.5 3.5' W=300db ST NA W= 300 lb NA = Normal force ; FA - frictioned force... + Frichones force 1" to the normal forces and frictional force opposite to the applied force.. FA = Mg NA FA = 0.4NA

to Efa=o +7 = 0.4x300 = 1 gold due to "FA FA=P Efy=0 W = NA NA = 300 lb P=FA=004 NA 120 lb But location "NA" Will not exact coincide with "W" why because it should comenter bedance Klockwise moment 7 "NA acts right to the "Gl point P = - max न 11 5 N 9

W=300 lb a 2013 3.51 - FA NA to EMG=0 ( NA xe) = ( x ) + ( FA X 3-5) 300(e) (120x]] +(120x3.5) = 540 300e e = 540 300 = 1.8 e=168ft from right to 6 point,