Homework Answers
Answer b. No, it is not possible. It is an obligate anaerobe, and have no reasons to have enzymes needed for aerobic respiration
Thyoglycolate broth is an enriched medium used in microbiology to determine the oxygen requirements of microorganisms. The organisms that grow at the bottom of the tube in thyoglycolate broth are obligate anaerobes.
The oxidase test is used for detecting the presence of the terminal enzyme system in aerobic respiration called cytochrome C oxidase. Being obligate anaerobes, they are devoid of oxidase enzyme because they metabolise energy anaerobically.
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Is it possible a bacterium that can only grow at the bottom of a tube of...
Is it possible a bacterium that can only grow at the bottom of a tube of...
Is it possible a bacterium that can only grow at the bottom of a tube of thioglycolate broth is also oxidase- positive? Why, or why not? Select one: a. Yes, it is absolutely possible. This bacterium is facultative anaerobic, so it uses oxidase to ferment glucose. b. No, it is not possible. It is an obligate anaerobe, and has no reason to have enzymes needed for aerobic respiration. O c. No, it is not possible. It can only use fermentation...
4) Fill in the following table: Oxygen DETOXIFYING ENZYMES Superoxide Catalase? dismutase? CLASSIFICATION ENERGY obtained by...
4) Fill in the following table: Oxygen DETOXIFYING ENZYMES Superoxide Catalase? dismutase? CLASSIFICATION ENERGY obtained by (Cellular respiration &/or fermentation) Requires/tole rates/inhibits prefers Obligate Aerobe Obligate anaerobe Facultative anaerobe Aerotolerant anaerobe Microaerophile 5) Match the following patterns of growth with the classification of bacteria. Growth throughout tube, equally distributed Growth throughout tube, heavier at top Growth at very top only Growth at very bottom only Growth at a defined spot, towards the top, but not at the very top
match the folowing regarding the Thrioglycolkqte Broth test: aero tolerant anaerobes obligate aerobes a microaerophile facultative...
match the folowing regarding the Thrioglycolkqte Broth
test:
aero tolerant anaerobes
obligate aerobes
a microaerophile
facultative anerobes
obligate anaerobes
Choose... Choose... A bacteria that requires lower levels of oxygen typically 2-10% 02 to survive, Normal(=21%) is present in the atmosphere (towards the top of the tube) A bacteria that makes ATP by aerobic respiration if oxygen is present, but is capable of switching to fermentation or anaerobic respiration if oxygen is absent. (mostly a the top and throughout the tube)...
find the unknown bacteria based on this results? List of possible Bacteria • Selective Unknown Bacteria...
find the unknown bacteria based on this results?
List of possible Bacteria • Selective Unknown Bacteria # 4. and Differential Media results for 4 Test MSA PEA Gram (+) to Bacillus cereus (bacillus) do 2. Bacillus mepeterum (becillus) 3. bacillus subtilis (bacillus) Blood 1-Starch Results Interpretation Presumptive ID red frowth Orpinism does not ferment manitol. Nonpathogenic No reochrom (-) good growth oganism is not inhibitelje gram Phenylethyl alcohol complete olipeskon 14 red blood cells on o nomeync activity B hemolytic...
Test Purpose Reagents Observation Results Gram To determines the identify the bacteria as a gram positive...
Test Purpose Reagents Observation Results Gram To determines the identify the bacteria as a gram positive or a gram negative. Crystal violet, iodine, Alcohol ,safranin Pink rods Gram negative rods Oxidase To determine the presence of cytochrome oxidase enzyme . Oxidase paper Lactose To determine if the bacteria can ferment carbohydrate . None Indole Test To determine the bacteria’s ability to decompose amino acid tryptophane to indole. Kovac added to1ml of trypotone broth Optimum Temp To determine the bacteria’s ability...
I need help creating a flowchart on a unknown 89 Chart of Unknown Test and the...
I need help creating a flowchart on a unknown 89 Chart of Unknown Test and the Result #89 Name of Test What does it test? Positive result appears as: negative results appears as: Unknown #89 result: Gram Stain Reaction Cell envelope morphology Violet-blue Red Negative (pink) Cell morphology (shape: coccus, bacillus, or spirillum) Cell shape Bacillus (Rod shaped) Cell Arrangement Cell size or length Single Bacillus Pigment Cell envelope morphology Pink Oxygen Requirement If cell needs oxygen for respiration Growth...
A ____________________ prefers to grow at temperatures between 25-40⁰C. A. barophile B. halophile C. mesophile D....
A ____________________ prefers to grow at temperatures between 25-40⁰C. A. barophile B. halophile C. mesophile D. psychrophile E. all of the above F. none of the above 2. In the aerobic respiration experiment, ________ bacteria will show a small amount of growth towards the top of the media; however, it is not growing at the surface, so no pellicle forms; the red layer of indicator is still present, and there is only a small amount of bacterial growth in the...
Microbiology ONLY answer 1 2 3 4 5 6 7 8 9 10 11 12 13...
Microbiology
ONLY answer
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Salmonella is associated with the handling of contaminated beef True False Escherichia coli is a red-pigmented organism. True O False The results of the MR-VP test can be directly read from the test without the addition of any other chemicals. True False Which medium contains a pH indicator to show pH change caused by fermentation? Glucose Broth Lactose Broth SIM Lactose and...
Create graphs for Figures 1-4 (circled on pages 111 & 114) based on the data given in Tables ...
Create graphs for Figures 1-4 (circled on pages 111 & 114)
based on the data given in Tables 2 & 4.
Lab # 8 Cellular Respiration and Fermentation I. Goals and Objectives At the completion of this laboratory exercise, students will be able to: A Differentiate between the intermediates and products of fermentation versus acrobic cellular respiration in yeast. Relate rates of fermentation with sugar availability in yeast. Utilize a reduction-oxidation dye to determine the effect of varying yeast concentration...
correct the ones marked wrong, and explain why they are the right answer Part I. Multiple...
correct the ones marked wrong, and explain why they are the
right answer
Part I. Multiple Choice. 1.5 points each, 32 questions, 48 points to Fill in the blank with the correct answer choice. 1. Which of the following is NOT required for microorganisms to grow and divide? ationefoliciningisson re edcorator als D replication b. binary fission um ormation injustt e@hours. This Cequatorial septum formation d. conjugation 2. A culture of Salmonella increases from 20 cells to over 10,000 cells...
Is it possible a bacterium that can only grow at the bottom of a tube of thioglycolate broth is also oxidase- positive? Why, or why not? Select one: a. Yes, it is absolutely possible. This bacterium is facultative anaerobic, so it uses oxidase to ferment glucose. b. No, it is not possible. It is an obligate anaerobe, and has no reason to have enzymes needed for aerobic respiration. O c. No, it is not possible. It can only use fermentation...
4) Fill in the following table: Oxygen DETOXIFYING ENZYMES Superoxide Catalase? dismutase? CLASSIFICATION ENERGY obtained by (Cellular respiration &/or fermentation) Requires/tole rates/inhibits prefers Obligate Aerobe Obligate anaerobe Facultative anaerobe Aerotolerant anaerobe Microaerophile 5) Match the following patterns of growth with the classification of bacteria. Growth throughout tube, equally distributed Growth throughout tube, heavier at top Growth at very top only Growth at very bottom only Growth at a defined spot, towards the top, but not at the very top
match the folowing regarding the Thrioglycolkqte Broth
test:
aero tolerant anaerobes
obligate aerobes
a microaerophile
facultative anerobes
obligate anaerobes
Choose... Choose... A bacteria that requires lower levels of oxygen typically 2-10% 02 to survive, Normal(=21%) is present in the atmosphere (towards the top of the tube) A bacteria that makes ATP by aerobic respiration if oxygen is present, but is capable of switching to fermentation or anaerobic respiration if oxygen is absent. (mostly a the top and throughout the tube)...
find the unknown bacteria based on this results?
List of possible Bacteria • Selective Unknown Bacteria # 4. and Differential Media results for 4 Test MSA PEA Gram (+) to Bacillus cereus (bacillus) do 2. Bacillus mepeterum (becillus) 3. bacillus subtilis (bacillus) Blood 1-Starch Results Interpretation Presumptive ID red frowth Orpinism does not ferment manitol. Nonpathogenic No reochrom (-) good growth oganism is not inhibitelje gram Phenylethyl alcohol complete olipeskon 14 red blood cells on o nomeync activity B hemolytic...
Microbiology
ONLY answer
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Salmonella is associated with the handling of contaminated beef True False Escherichia coli is a red-pigmented organism. True O False The results of the MR-VP test can be directly read from the test without the addition of any other chemicals. True False Which medium contains a pH indicator to show pH change caused by fermentation? Glucose Broth Lactose Broth SIM Lactose and...
Create graphs for Figures 1-4 (circled on pages 111 & 114)
based on the data given in Tables 2 & 4.
Lab # 8 Cellular Respiration and Fermentation I. Goals and Objectives At the completion of this laboratory exercise, students will be able to: A Differentiate between the intermediates and products of fermentation versus acrobic cellular respiration in yeast. Relate rates of fermentation with sugar availability in yeast. Utilize a reduction-oxidation dye to determine the effect of varying yeast concentration...
correct the ones marked wrong, and explain why they are the
right answer
Part I. Multiple Choice. 1.5 points each, 32 questions, 48 points to Fill in the blank with the correct answer choice. 1. Which of the following is NOT required for microorganisms to grow and divide? ationefoliciningisson re edcorator als D replication b. binary fission um ormation injustt e@hours. This Cequatorial septum formation d. conjugation 2. A culture of Salmonella increases from 20 cells to over 10,000 cells...
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