Question

The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If Oc= 40.4º what is the index of refraction of the material? 1.54 You are correct. Previous Tries A light ray strikes this material (from air) at an angle of 37.2° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). 23.07 Submit Answer Incorrect. Tries 3/20 Previous Tries Calculate the angle of the refracted ray (in degrees). Submit Answer Tries 0/20 Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.2° with respect to the normal. What is the angle of the refracted ray? Submit Answer Tries 0/20

Answer 1

air 1=37.29 8 W If angle of refraction is Oorefy, then Adress ng = 1:54 Angle of reflection Ovefl = 1 = 37.2 by Shell's law Sinli) = ng Sin Orefy Sin (37.2%) = 1.54 Sin (Oref) Orefs= 23.10 & Angle of refracted ray is 23.1 Ans n=1:54 cing 37:2° - let angle of refracted say is is o, then by shell's law nsin (2) = sin => 1.54 xsin (37.2°) = sin o = [0= 68.6° An