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a n b b Activity C, E E A Activity А 6 B 2 с 8 D 5 E 6 8 8 12 6 3 9 E Immediate Predecessor(s) G 3 3 5 Н 2 2 2 I 5 5 5 J 4 7
a.) Create project network for activites A thru G
b.) Then compute on the network above, the correct Activity on Arrow format (AOA), the earliest start, earliest finish, latest start, and latest finish times for project.
business   Operations-Management   
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Answer #1

B (9:67 3 E(2.84) A(1015) I(5) 1 A(8) C(12) 2 4 7 Kiz 8 D(6.57 (71(3.33 H29 KG F135) 6

A B C D E F H J K L M 1 2 a m b Mean time EF LS LF Slack Activity Predecessor A ES 0 3 6 8 10 8 0 4 B A 2 8 24 8 9.666666667

Formulas used are shown in the below table,

J 1 =K3-G3 B -KE.CE K6-16 Line COR. CONC А B D E F H 1 K L 2 Activity Predecessor m b Mean time ES EF LS LF Slack 3 А 6 8 10

Formulas used to calculate ES,EF,LS and LF are shown below:

Forward pass -

ES = Maximum(EF of the predecessor activities)

EF = ES + Mean time

Backward pass -

LF = Minimum(LS of all succeeding activities)

LS = LF - Mean time

Note,

ES for Activity A = 0

LF for activity K = EF for activity K

Critical path is the path with the activities with zero slack

Hence,

critical path is A-B-E-F-H-J-K

Time required for critical path = 43.5 units of time.

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