Question

Exercise Five: (Parallel Array) In this exercise create two string arrays. One array will hold your name, another will hold corresponding password. Example: string name [] = {"name1","name2", "name3"}; string password [] = {"password1", "password2", "password3"}; Here for name1, matching password is password1, name2, matching password is password2 and so on.... Please ignore my creativity, you can pick name and password your way and it doesn't have to have just 3 names and password. It can be less/more. I am using just 3 for convenience. Ask the user to enter the name and password. Check, they are matching or not. If it's a match, Display it's match otherwise display it's not a match. Note: • name and password array size has to be same. • You must calculate the length of the array. For the length, just do not write 3. That way, you can add one more name and password any time. • for each name, you look for the password at corresponding index. Ex: If name is at index 1. you look for the password at index 1 only. Not the entire array of password. . You should display only one time, It's matching or It's NOT matching. • It's case-sensitive.

Answer 1

#include<iostream>
#include<string>
using namespace std;
//function to search for the name in the array
int search(string name[], string uname, int n)
{
   //iterate over the array
   for(int i = 0;i < n;i++)
   {
       //if the name in array if equal to the given name, return the index
       if(name[i] == uname)
       {
           return i;
       }
   }
   //if the name not found in the array return -1
   return -1;
}

int main()
{
   //create two parallel arrays
   string name[] = {"name1", "name2", "name3"};
   string password[] = {"password1", "password2", "password3"};
  
   //prompt the user to enter name
   cout<<"Enter your name: name: ";
   string uname;
   cin>>uname;
   //prompt the user to enter password
   cout<<"Enter your password: ";
   string pass;
   cin>>pass;
   //calculate the size of the array
   int n = sizeof(name)/sizeof(name[0]);
   //search the name in the names array
   int index = search(name, uname, n);
   if(index != -1)
   {
       //if the current name and password are at the same index in parallel arrays
       if(password[index] == pass)
       {
           //match them
           cout<<"It's matching!"<<endl;
       }
       else
       {
           //otherwise they are not matching
           cout<<"It's NOT matching!"<<endl;
       }
   }
   //if the name not found in the array, they are not matching
   else
   {
       cout<<"It's NOT matching!"<<endl;
   }
}

EN Activities Terminal - Thu 06:28 deepika@deepika-TravelMate-P243-M: -/Desktop File Edit View Search Terminal Help deepika@deepika-TravelMate-P243-M:~/Desktop$ 9++ parallel_array.cpp deepika@deepika-TravelMate-P243-M :-/Desktop$ ./a.out Enter your name: name: name2 Enter your password: password2 It's matching! deepika@deepika-TravelMate-P243-M :-/Desktop$ ./a.out Enter your name: name: name2 Enter your password: password1 It's NOT matching! deepika@deepika-TravelMate-P243-M:~/Desktop$ ./a.out Enter your name: name: nidhi Enter your password: tilak It's NOT matching! deepika@deepika-TravelMate-P243-M:-/Desktops I

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