Question

An ac source 9 sin(601) Vis connected in series across Capacitor and diode. The turn on voltage of the diode lis 1 Use the CVD model. The value of the capacitor is 5 microfarad. The charge on the plates of the capacitor is 5 micro-Coulombs attoo, with the left plate of the capacitor being at a higher voltage than the right plate of the capacitor Plot the voltage across the capacitor starting at to for two full time periods of the source • It might help to put a ground at the lower node • USE OF LTSPICE IS NOT ALLOWED in this or any other question, intermediate steps in analysis have to be shown 11) An ac source 9 sin(604) Visconnected in series across a capacitor and diode. The turn on voltage of the diode is IV. Use the CVD model. The value of the capacitor is 5 microfarad. The charge on the plates of the capacitor is 5 micro-Coulomos atte, with the lett plate of the capacitor being at a higher voltage than the right plate of the capacitor. Pot the voltage across the capacitor starting at t=0 for two full time periods of the source ho Ground

Answer 1

Oo (Vo) 1 C=54F 9 8inbot tu Vold. SHO Vo = - FI Volt. SHE Voltage across Capaciter will be Veld - g Sinbot - 1 t Velo) = gsinbot Capacitor is charging when value of Current will be positive. Otherwise Circuit Reached at ss. i= c dvelds - Soccoshof dt [ costo 4 x 60 Copaciter is charging fer fe [o. 2/2) (99,24] ferom pois.

For de Co, a] Capaciter charged upto guolt which is Samo Source monimum Voltage. After the Circuit Current will be 2000 So Capaciter Reaches at Steady state and Veld will be g Volt velt 9v 7 wt No 49

Thanks.