Question

In all what follows, the sampling frequency is fixed to fs = 40KHz. Part 2 - Pre-Aliasing Filter As a preventive measure, a p

0 0
Add a comment Improve this question Transcribed image text
Answer #1

gfiller 9) Pre-ab alasing Advantages :) If remove unwanted higher frequencies which causes frequency overlapping 1) Prevents S

Add a comment
Know the answer?
Add Answer to:
In all what follows, the sampling frequency is fixed to fs = 40KHz. Part 2 -...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A Digital Signal Processing system is taking at its input the following analogue signal s(t); s(t)...

    A Digital Signal Processing system is taking at its input the following analogue signal s(t); s(t) - 20+ 20 cos(24xt)cos(xt), Where time t is expressed in ms. Part 1 - Setting the sampling frequency: (11 Marks) As a start, the system comprises only a sampler and an ideal analogue reconstructor as follows: w(t) s(t) Sampler Analogue Reconstructor s,(t) Figure a) Find the frequency spectrum S(t) of s(t) and deduce its bandwidth. You may directly use the table provided at the...

  • Consider a sampler which samples the continuous-time input signal x(t) at a sampling frequency fs =...

    Consider a sampler which samples the continuous-time input signal x(t) at a sampling frequency fs = 8000 Hz and produces at its output a sampled discrete-time signal x$(t) = x(nTs), where To = 1/fs is the sampling period. If the sampled signal is passed through a unity-gain lowpass filter with cutoff frequency of fs/2, sketch the magnitude spectrum of the resulting signal for the following input signals: (a) x(t) = cos(6000nt). (b) x(t) = cos(12000nt). (c) x(t) = cos(18000nt).

  • 3 Sampling and aliasing The aim of this part is to demonstrate the effects of aliasing...

    3 Sampling and aliasing The aim of this part is to demonstrate the effects of aliasing arising from improper sampling. A given analog signal z(t) is sampled at a rate fs = 1/T, the resulting samples (nT) are then reconstructed by an ideal reconstructor into the analog signal rat). Improper choice of f, will result in different signals ra(t) + (t), even though they agree at their sample values, that is, tanT) = x(nT). The procedure is illustrated by the...

  • number 2 ECE 300 Continuous-Time Signals and Systems H(jø π/2 Plot the spectrum Z (jø) of the filtered input signal z()...

    number 2 ECE 300 Continuous-Time Signals and Systems H(jø π/2 Plot the spectrum Z (jø) of the filtered input signal z(), the spectrum Z, (jo) of the sampled signal z.(t), and the spectrum Y(ja) of the reconstructed signal y(t). Show clearly how the output spectrum Y (ja) differs from the original spectrum G(jo) C. Which system, A or B, produces less distortion between the input g(t) and the output y(4) or ()? Explain. You can measure distortion by finding the...

  • 3.(30 points) Pulse Code Modulation A-to-D Ideal Lowf Pass Filter xit)- #x) cos(2rfet) (10 points...

    3.(30 points) Pulse Code Modulation A-to-D Ideal Lowf Pass Filter xit)- #x) cos(2rfet) (10 points) Consider the system in the above figure. The ideal low pass filter is one which has a brick-wall frequency response (or an ideal sinc function for its impulse response). If the bandwidth of the ideal low pass filter is IkHz and B 2kHz is the bandwidth of a bandpass signal x(t) that is centered at fo 19700Hz, determine the minimum sampling rate fs to avoid...

  • Problems: 1. Consider the system shown below. Let the input signal to the Ideal Sampler to be: s(...

    just looking for #2, 3, and 4 Problems: 1. Consider the system shown below. Let the input signal to the Ideal Sampler to be: s(t) = 2 cos(2m50t) + 4cos(2m100t) a. (10 points) Determine S(f) and plot it b. (20 points) Let the sampling rate to be: fs 300 samples/sec. Plot the spectrum of the Ideal sample, that is plot S8(f) c. Let the sampling rate to be: fs 175 samples/sec. i. (30 points) Plot S8(f) ii. (10 points) Let...

  • Program from problem 1: (Using MATLAB) % Sampling frequency and sampling period fs = 10000; ts...

    Program from problem 1: (Using MATLAB) % Sampling frequency and sampling period fs = 10000; ts = 1/fs; % Number of samples, assume 1000 samples l = 1000; t = 0:1:l-1; t = t.*ts; % Convert the sample index into time for generation and plotting of signal % Frequency and amplitude of the sensor f1 = 110; a1 = 1.0; % Frequency and amplitude of the power grid noise f2 = 60; a2 = 0.7; % Generating the sinusoidal waves...

  • 2. Consider the signal f(t) = 20 cos(5t) + cos(9t) sin(5t) - 7 (a) What is the highest angular frequency present in thi...

    2. Consider the signal f(t) = 20 cos(5t) + cos(9t) sin(5t) - 7 (a) What is the highest angular frequency present in this signal? What is the highest numerical frequency present in this signal? (b) What is the Nyquist frequency? rate for this signal? Did you use the angular or the numerical (c) If you sample this signal with sampling period T, which values of T may you choose to be in accordance with the Nyquist rate? Choose and fix...

  • Part A:- Synthesising a Discrete Signal using Matlab: Using a sampling frequency of 8000 Hz, determine...

    Part A:- Synthesising a Discrete Signal using Matlab: Using a sampling frequency of 8000 Hz, determine the discrete signal, x[n] that is obtained from sampling a 1000 Hz sine wave, with a peak magnitude of 0.8. (that is, x(t)-0.8cos(2rtft)). Determine an equation for xin] in terms of 'n' and then create the signal in Matlab. (Remember in this case 'n' is your independent variable not t'.) Play the x[n] signal through the PC soundcard using the 'sound' command in Matlab....

  • matlab help, please my code is here: %% exercise2 %a Fs = 8000; % sampling frequency tn = 0:1/Fs:0.005; % here, bit dura...

    matlab help, please my code is here: %% exercise2 %a Fs = 8000; % sampling frequency tn = 0:1/Fs:0.005; % here, bit duration is 0.005s instead of 1/300s phi1 = 0; phi0 = 0; % phases of the sinusoid x1 = cos(2*pi*1650*tn + phi1); % tone for binary 1 x0 = cos(2*pi*1850*tn + phi0); % tone for binary 0 xx = [x1, x0]; % FSK signal for ¡°1,0¡± tt = [tn, tn + 0.005]; % time figure(1) plot(tt, xx); %...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT