Question

C++ Language

Given an array length 1 or more of ints, return the difference between the largest and smallest values in the array. Examples: largeDiff (410, 3, 5, 6}, 4) - 7 largeDiff ({7, 2, 10, 9}, 4) - 8 largeDiff ({2, 10, 7, 2}, 4) + 8 largeDiff ({2}, 1) = 0 code.cpp + New I Full Screen 2- int largeDiff (const int a[], int n) { 3 4 5}

Answer 1

Function:

int largeDiff(const int a[], int n) //function
{
int mini=a[0], maxi=a[0]; //initializing minimum and maximum are of first element.
int diff;
for(int i=1; i<n; i++) // reading second element to last element in array.
{
if(a[i] > maxi) //if any number is more than maximum then updating the maximum.
maxi = a[i];

if(a[i] < mini) //if any number is less than minimum then updating the minimum.
mini = a[i];
}
diff = maxi-mini; //calculating difference between maximum and minimum.
return diff; //returning difference.
}

int largeDiff (const int a[], int n) //function int mini-a [0], maxi=a[0]; //initializing minimum and maximum are of first element. int diff; for (int i=1; i<n; i++) // reading second element to last element in array. if(a[i] > maxi) //if any number is more than maximum then updating the maximum. maxi = a[i]; if(a[i] < mini) //if any number is less than minimum then updating the minimum. mini = a[i]; } diff = maxi-mini; //calculating difference between maximum and minimum. return diff; //returning difference. -)

Program:

#include<iostream>
using namespace std;
int largeDiff(const int a[], int n) //function
{
int mini=a[0], maxi=a[0]; //initializing minimum and maximum are of first element.
int diff;
for(int i=1; i<n; i++) // reading second element to last element in array.
{
if(a[i] > maxi) //if any number is more than maximum then updating the maximum.
maxi = a[i];

if(a[i] < mini) //if any number is less than minimum then updating the minimum.
mini = a[i];
}
diff = maxi-mini; //calculating difference between maximum and minimum.
return diff; //returning difference.
}
int main()
{ //declaring arrays and calling the function and printing the result.
int a[] = {10, 3, 5, 6};
cout << largeDiff(a, 4) << endl;

int b[] = {7, 2, 10, 9};
cout << largeDiff(b, 4) << endl;

int c[] = {2, 10, 7, 2};
cout << largeDiff(c, 4) << endl;

int d[] = {2};
cout << largeDiff(d, 1) << endl;
return 0;
}

1 2 3 #include<iostream> using namespace std; int largeDiff (const int all, int n) //function 4 5 int mini=a[0], maxi=a[0]; //initializing minimum and maximum are of first element. int diff: for (int i=1; i<n; i++) // reading second element to last element in array. ܒܝܢ if(a[i] > maxi) //if any number is more than maximum then updating the maximum. maxi = a[i]; if(a[i] < mini) //if any number is less than minimum then updating the minimum. mini = a[i]; } between aximum and minimum. diff = maxi-mini; //calculating differenc return diff; //returning difference. } 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 int main() //declaring arrays and calling the function and printing the result. int a[] = {10, 3, 5, 6); cout < largeDiff(a, 4) << endl; int b[] {7, 2, 10, 9); cout << largeDiff (b, 4) << endl; int cl {2, 10, 7, 2}; cout < largeDiff(c, 4) << endl; int d[ ] {2}; cout << largeDiff(d, 1) << endl; return 0; }

output:

7 8 8 CO Process returned @ (exe) execution time : 0.021 s Press any key to continue.

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