The rate is 2.75%Homework Answers
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The rate is 2.75%
5. Copmare the following 2 altrernatives using the Net Equivalent Uniform Annual...
Compare the following 2 alternatives using the Net Equivalent Uniform Annual (NEUA) method and the given...
Compare the following 2 alternatives using the Net Equivalent Uniform Annual (NEUA) method and the given interest rate of 4.5% Draw the Cash Flow Diagram Alt. Construction cost $ Benefit ($/yr) Salvage $ Service Life (yrs) A 1,800,000 400,000 40,000 7 B 2,900,000 550,000 80,000 14
Compare the following 2 alternatives using the Net Present Worth (NPW) method – rate is 4.5%...
Compare the following 2 alternatives using the Net Present Worth (NPW) method – rate is 4.5% per year. Repeat the solution using the Net Equivalent Uniform Annual (NEUA) method. Which one is simpler? Draw all cash flow diagrams. Alt. Construction Cost Benefit Maintenance Service Life A $380,000 $240,000/yr. $10,000/yr. 9 yrs B $750,000 $270,000/yr. $20,000/yr. 18 yrs
6. Compre the following alternatives using the Net Equivalent Uniform Annual Worth method. Alt. Construction cost...
6. Compre the following alternatives using the Net Equivalent Uniform Annual Worth method. Alt. Construction cost $ Life (yrs) A $30million 40 B $35million Infinite
Compare the following 2 alternatives using the Net Present Worth (NPS) method – rate is 3%...
Compare the following 2 alternatives using the Net Present Worth (NPS) method – rate is 3% per year. Draw all cash flow diagrams. Please show work using a formula. Alt. Construction Cost ($) Benefit ($/yr.) Service Life (yrs.) A 380,000 200,000 7 B 450,000 220,000 7
Find the equivalent uniform annual cost 3. Using an interest rate of 12%, find the equivalent miform annual cost for a piece of construction equipment that has an initial purchase cost o $30,000,...
Find the equivalent uniform annual cost
3. Using an interest rate of 12%, find the equivalent miform annual cost for a piece of construction equipment that has an initial purchase cost o $30,000, an estiinat nomic life of 8 years, and an estimated salvage value of $10,000. Annual mainte- nance will anount to $600 per year and periodic overhauls costing $1.,000 each will occur at the end of the second, fourth, and sixth years.
3. Using an interest rate of...
Compare the following alterntives given a market rate of 5.45% per year and an inflation rate...
Compare the following alterntives given a market rate of 5.45% per year and an inflation rate of 3% per year. Use first the B/C method to determine feasibility and then the incremental B/C method to determine the oprimum level of investment. Alt Construction Cost $ Annual Benefits $/yr Life yrs A 105,000 40,000 5 B 230,000 52,000 6 C 350,000 64,000 7 D 600,000 100,000 8
Compare the following alterntives given a market rate of 5.45% per year and an inflation rate of 3% per year. Use firs...
Compare the following alterntives given a market rate of 5.45% per year and an inflation rate of 3% per year. Use first the B/C method to determine feasibility and then the incremental B/C method to determine the oprimum level of investment. Alt Construction Cost $ Annual Benefits $/yr Life yrs A 105,000 40,000 5 B 230,000 52,000 6 C 350,000 64,000 7 D 600,000 100,000 8
a) determine which machine should be purchased, based on equivalent uniform annual cost. b) what would...
a) determine which machine should be purchased, based on
equivalent uniform annual cost.
b) what would be the MACRS depreciation in the third year for
machine II?
11-44 A company is considering buying a new piece of machinery. A 10% interest rate will be used in the computations. Two models of the machine are available. sloboibos trolinis ob hoi Machine | Machine II Initial cost odos $100,000 le 25,000 $80,000 od 000. End-of-useful-life 20,000 salvage value, s Annual operating 18,000...
4. Compare the following altemtives given a market rate of 3.45% per year and an inflation...
4. Compare the following altemtives given a market rate of 3.45% per year and an inflation rate of 3% per year. Use first the B/C method to determine feasibility and then the incremental B/C method to determine the oprimum level of investment. Life yrs Alt A Construction Costs Annual Benefits S/yr 105,000 40,000 230,000 52.000 350.000 64,000 600,000 100,000 6
5. Compare the following two alternatives by the IRR method, given MARR of 8%/year. Is the...
5. Compare the following two alternatives by the IRR method, given MARR of 8%/year. Is the incement in cost form A to B justified? Alt. Construction cost | Benefits Styr | Salvage Service Life (yrs 510,000 145,000 10,000 775,000 155,000 20,000
6. Compre the following alternatives using the Net Equivalent Uniform Annual Worth method. Alt. Construction cost $ Life (yrs) A $30million 40 B $35million Infinite
Find the equivalent uniform annual cost
3. Using an interest rate of 12%, find the equivalent miform annual cost for a piece of construction equipment that has an initial purchase cost o $30,000, an estiinat nomic life of 8 years, and an estimated salvage value of $10,000. Annual mainte- nance will anount to $600 per year and periodic overhauls costing $1.,000 each will occur at the end of the second, fourth, and sixth years.
3. Using an interest rate of...
a) determine which machine should be purchased, based on
equivalent uniform annual cost.
b) what would be the MACRS depreciation in the third year for
machine II?
11-44 A company is considering buying a new piece of machinery. A 10% interest rate will be used in the computations. Two models of the machine are available. sloboibos trolinis ob hoi Machine | Machine II Initial cost odos $100,000 le 25,000 $80,000 od 000. End-of-useful-life 20,000 salvage value, s Annual operating 18,000...
4. Compare the following altemtives given a market rate of 3.45% per year and an inflation rate of 3% per year. Use first the B/C method to determine feasibility and then the incremental B/C method to determine the oprimum level of investment. Life yrs Alt A Construction Costs Annual Benefits S/yr 105,000 40,000 230,000 52.000 350.000 64,000 600,000 100,000 6
5. Compare the following two alternatives by the IRR method, given MARR of 8%/year. Is the incement in cost form A to B justified? Alt. Construction cost | Benefits Styr | Salvage Service Life (yrs 510,000 145,000 10,000 775,000 155,000 20,000
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