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- An equal-tangent crest vertical curve is designed for 65 mi/h. The initial grade is +3.4% and the final grade is negative. What is the elevation difference between the PVC and the high point of the curve?
An equal tangent crest vertical curve is designed for 60 mph. The initial grade is +4.0% and the final grade is negative. What is the elevation difference between the PVC and high point of the curve?
An equal-tangent crest vertical curve has a 50-mi/h design speed. The initial grade is +3%. The high point is at station 33 + 40.76 and the PVT is at station 37 + 24.66. What is the elevation difference between the high point and the PVT?
(10 pts) A crest curve with an initial tangent grade of 3.7% and a final tangent grade of-4.1% has a length of 1400 feet. What is the maximum recommended speed limit for the curve?
2. A crest vertical curve is to be designed by joining a +4% initial tangent with a final -3% tangent. The station location and elevation of VPC are 250+45 and 500 ft respectively. The design speed is 50 mph on the curve. Using AASHTO geometric design guideline, determine: (a) Station location of VPT. (b) Vertical offset at each 1/4 of length distance from VPC.
4. A vertical curve is designed for 55 mi/h and has an initial grade of 2.5% and a final grade of -1.0%. The PVT is at station 114 + 50. It is known that a point on the curve at station 112 + 35 is at elevation 245 ft. What is the stationing and elevation of PVC?
An equal-tangent crest vertical curve was designed in 2012 (to 2011 AASHTO guidelines) for a design speed of 70 mph to connect grades G1 = +1.2% and G2 = -2.1%. The curve is to be redesigned for a 70 mph design speed in the year 2025. Vehicle braking technology has advanced so that the recommended design deceleration rate is 25% greater than the 2011 value used in Table 3.1, but due to the higher percentage of older persons in the...
A 600 feet sag vertical curve (equal tangent) has a PVC at station 100+00 and elevation 300 feet. The initial grade is -3.5 % and the final grade is +5.5%. Determine the elevation and stationing of the lowest point, PVI, and PVT.
An equal tangent vertical curve of length 420 ft connects a +2.25 % initial grade and a -2.75 % final grade. What is the design speed of the curve?
An equal-tangent vertical curve connects an initial grade of +2% and-2%. The PVI is located at an elevation of 1000 feet. If the design speed is 60 mi/h and the curve is designed for stopping sight distance, then what is the elevation of the PVT, in feet?
13. A 400-ft long equal tangent sag vertical curve has its PVC at station 100+00 and o b elevation 500 ft, the initial grade g,--4% and the final grade g2 elevation of the lowest point of the curve. +2.5%. Determine the