Calculate the molarity (M) of a 23% (w/v) copper sulfate solution (m.w. = 160.0 g/mol).
Answer: Molarity (M) of a 23% (w/v) copper sulfate solution:
Molarity = number of moles of solute / litres of solution
23% means 23g of Copper sulfate in 100mL of solution
Molecular weight of Copper sulfate is 160.0 g/mol
This means
160g = 1 mole of copper sulfate molecules
23g in 100mL solution = 23/160 moles = 0.144 moles of copper sulfate molecules in 100 mL solution
Molarity is no. of moles per L of solution.
So, converting the units, we get
Molarity = 0.144 moles/100mL = 1.44 moles/L (Answer)
Calculate the molarity (M) of a 23% (w/v) copper sulfate solution (m.w. = 160.0 g/mol).
A solution of copper (II) sulfate (CuSO_4) in water is 11.00% copper (II) sulfate by mass. Its density is 1.1186 g cm^3 at 20 degree c. Compute its molarity, mole fraction, and molality at this temperature. Molarity CuSO_4 = M Mole fraction CuSO_4 = Molality CuSO_4 = m.
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Calculate the osomolarity of 0.5 g/mL of magnesium sulfate
heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol
Calculate the osmolarity of 1 Liter of solution that contains
40mEq of sodium, 20 mEq of potassium, 60 mEq of chlorine and 5% w/v
of dextrose (mol way: 180 non-electrolyte).
My teacher gave me the answer but I didn't understand how they
got it. thank you.
2. Calculate the osmolarity of 0.5 g/mL of magnesium sulfate heptahydrate - MgSOa.7H20 MW-246.47 g/mol 0.59 Calculate the osmolarity of...
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