Question

Name: ET-3601 Homework for chapter 10. 1. Find the capacitance of a parallel plate capacitor if 1200uC of charge are deposited on its plates when 24V are applied across the plates. 2. Find the Capacitance of a parallel plate capacitor if the area of each plate is 0.1m and the distance of each plate is 0.1 inch. The dielectric is air. 3. Referring to p.454, # 19 (in your text book), what is the time constant of figure 10.94 if the resistor is 100 K Ohms and the capacitor is 5.6uF?

Answer 1

sol (1) given We know a = 1200 uc V-28V so cv ce a ас: 1200 uc 200 = 50 uf (2.) given We know A= 0.1 m² d = id inch= 0.00254m ca Cotr A Grad for air O -10 - 8.85 X10 XIX. 1 3.48 +2 X10 .00 254 3.1 e-398.92x1525 – 398.42 &F/ given R = 100kr - 5.6 MF Time Constant T-RC = 100 x 103 x 5.681 1 = 0.55 sec C = (blf + suf) ISUF +12 41F). 10x20 euf = 6.67 UFC of buf ble H 30 12 ur bu Coq 1205 ceg = 4.3636 4F given (= 1200F = 12v energy stored by capacitor = Ź Cv². - 1/2 120 x10m x 12*12 = 8.64 x 10 joule = 8.14 nj