Question

JAVA language

CSE110 Principles of Programming Assignment 02.10 pts Assignment 02:100 pts CSE110 Principles of Programming Test #2 Given Inputs Length of road project (miles) : 3 Number of lanes Depth of asphalt (inches) 18 Days to complete project : 50 1. The trucks hauling asphalt have a maximum capacity of 5 US tons (10,000 lbs 2. The standard road lane is 12 feet wide. 3. Asphalt welghs 150 lbs per cubic foot 4. Asphalt costs $200 per ton 5. Power and water utilities are run in a conduit pipe under the road as part of all road projects 6. Conduit pipe is available only in 24 ft. lengths cach length costs $500 7. There is one intersection for every mile of road a. a 1 mile road has 1 intersection b. a 2 mile road has Z intersections c. a 2.99 mile road has 2 intersections 8. Stoplights cost $25,000 per light 9. Each intersection has two stoplights, plus one additional stoplight for each lane a. a 1 lane road has three stop lights at each intersection b. a 2 lane road has four stop lights at each intersection L. a 3 lane road has five stop lights at each intersection 10. Work days are 8-hour days 11. All workers are paid $25 per hour. 12. Crew members can complete an amount of work in a specified time according to the equation below: Expected Output --- Amount of materials needed --- Truckloads of Asphalt : 8554 Stoplights : 12 Conduit pipes 668 Crew members needed : 6 === Cost of Materials E EEEE==== Cost of Asphalt : $8554800.00 Cost of Stoplights : $3e0neo.80 Cost of Conduit pipes : $330000.0 Cost of Labor : $6e0ne.00 === Total Cost of Project ======== Total cost of project : $9244800.00 50. miles . lanes crew Member == days Test Data Test #3 Given Inputs Length of road project (miles) : 1 Number of lanes Depth of asphalt (inches) : 1 Days to complete project Test #1 Given Inputs Length of road project (miles) : 2.75 Number of lanes Depth of asphalt (inches) 12 Days to complete project 30 Expected Output === Amount of materials needed === Truckloads of Asphalt : 7841 Stoplights ! 10 Conduit pipes 695 Crew members needed 14 === Cost of Materials ============ Cost of Asphalt ! $7841900.ee Cost of Stoplights : $250000.00 Cost of Conduit pipes : $392588.oe Cost of Labor $84800.00 --- Total Cost of Project -------- Total cost of project : $8477580.60 Expected Output === Amount of materials needed === Truckloads of Asphalt : 88 Stoplights Conduit pipes : 220 Crew members needed : 50 === Cost of Materials ============ Cost of Asphalt : $80080.80 Cost of Stoplights : $75000.00 Cost of Conduit pipes : $110000.00 Cost of Labor : $1ease, === Total Cost of Protect ======== Total cost of project : $275880.80

Answer 1

Code:

import java.lang.Math;
import java.util.Scanner;

public class Road {
   public static void main(String[] args) {
       // Scanner object to get user input
       Scanner sc = new Scanner(System.in);

       // variables to store user input
       double length, depth; // length of road, depth of asphalt
       int lanes, days; // number of lanes, number of days

       // getting user input
       System.out.print("Length of road project (miles): ");
       length = Double.parseDouble(sc.nextLine()); // getting input as a string then parsing int
       System.out.print("Number of lanes : ");
       lanes = Integer.parseInt(sc.nextLine());
       System.out.print("Depth of asphalt (inches) : ");
       depth = Double.parseDouble(sc.nextLine());
       System.out.print("Days to complete project : ");
       days = Integer.parseInt(sc.nextLine());

       // calculating materials required
       double asphalt = ((length*5280)*lanes*depth)*150/2000;
       int truckLoads = (int)Math.round(asphalt/5);
       int intersections = (int)length;
       int conduitPipes = (int)(length*5280)/24; // convert the miles to feet and divide by 24
       int stoplights = (lanes + 2)*intersections;
       int crewMembers = (int)Math.round((50*length*lanes)/days);
       // calculating cost of materials
       double costOfAsphalt = truckLoads*1000;
       double costOfStoplights = stoplights*25000;
       double costOfPipes = conduitPipes*500;
       double costOfLabor = crewMembers*days*8*25;
       double totalCost = costOfAsphalt + costOfStoplights + costOfPipes + costOfLabor;

       // printing all the outputs
       System.out.println();
       System.out.println("=== Amount of materials needed ===");
       System.out.println("Truckloads of Asphalt : "+truckLoads);
       System.out.println("Stoplights : "+stoplights);
       System.out.println("Conduit pipes : "+conduitPipes);
       System.out.println("Crew members needed : "+crewMembers);
       System.out.println("=== Cost of Materials ============");
       System.out.printf("Cost of Asphalt : $%.2f\n", costOfAsphalt);
       System.out.printf("Cost of Stoplights : $%.2f\n", costOfStoplights);
       System.out.printf("Cost of Conduit pipes : $%.2f\n", costOfPipes);
       System.out.printf("Cost of Labor : $%.2f\n", costOfLabor);
       System.out.println("=== Total Cost of Project ========");
       System.out.printf("Total cost of project : $%.2f\n", totalCost);
   }
}

OUTPUT: