By work energy theorem

= (1/2)m(v2 - u2)
(F×8)+(-5000) = (1/2)×200×(252 -152)
8F -5000 = 40000
8F = 45000
F = 5625 N
(Note that work done by applied force is equal to force multiplied by displacement as both are in same direction.
is change in kinetic energy)
8. An object (mass = 200 kg) is pushed up a friction- less inclined plane (0)...
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XV F
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