1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite...
Diamon and graphite are two crystalline forms of
carbon. At 1 atm and 25°C, diamond changes to graphite so slowly
that the enthalpy change of the process must be obtained
indirectly. Determine delta H rxn for C(diamond) >
C(graphite)
with equations from the following list:
Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond)...
Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ...
5. Use the following data to determine the delta H for the conversion of diamond into graphite: C(diamind) (s) + O2(g) = CO2(g) delta H degrees = -395.4 kJ 2CO2(g) = 2 CO(g) + O2(g) delta H degrees = 566.0 kJ 2CO(g) = C(graphite) (s) + CO2 (g) delta H degrees = -172.5 kJ C(diamond) (s) = C(graphite) delta H degrees = ?
Enter your answer in the provided box From the following data, C(graphite) + O2(0)+ CO2(g) An° . =-393.5 kJ/mol rxn Hy(@) +0,6) H200 AH =-285.8 kJ/mol rxn 2C2H6(8) + 1026) →40026) + 6H20(1) AH =-3119.6 kJ/mol rxn calculate the enthalpy change for the reaction below: 2 C(graphite) + 3H2(g) → CH()
Enter your answer in the provided box Use the following data to calculate ΔΗο for CS20: C(graphite)+ O2(8)-Co2() S(rhombic) +02(g) → SO2(g) CS2(0) + 302(8) CO2(8) + 2S02(3) o AH =-393.5 kJ/rnol rxn AH296.4 kJ/mol rxn AHorn =-1073.6 kJ/mol 0
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
Please explain
Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
9.Enter your answer in the provided box. S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/mol S(monoclinic) + O2(g) → SO2(g) ΔHo rxn= −296.36 kJ/mol calculate the enthalpy change for the transformation S(rhombic) → S(monoclinic) (Monoclinic and rhombic are different allotropic forms of elemental sulfur.) _______kJ/mol 10. Enter your answer in the provided box Use the following data to calculate ΔHo/f for CS2(l): C(graphite) + O2(g) → CO2(g) ΔHo rxn= −393.5 kJ/mol S(rhombic) + O2(g) → SO2(g) ΔHo rxn=...
3 attempts left Check my work Enter your answer in the provided box. Calculate AG for the reaction at 25°C. 2C6H61) + 1502(8) 12C028) + 6H20(1) agº = kJ AH° (kJ/mol Agº (kJ/mol) sº (J/K mol) 5.69 2.4 Substance C(graphite) C(diamond) CO(g) CO2(g) CO2(aq) C0,- (aq) O(g) O2(8) O3(aq) O3(8) H20(1) CH 1.90 -110.5 -393.5 -412.9 -676.3 249.4 2.87 --137.3 -394.4 -386.2 --528.1 230.1 0 16.3 163.4 -237.2 124.5 197.9 213.6 121.3 -53.1 160.95 205.0 110.88 237.6 -12.09 142.2 -285.8...
2. (10 pts) Given the following data Ca(s)2C(graphite)CaC2(s) -62.8 kJ OH635.5 Ca(s)1/202(g) CaO(s) kJ CaO(s)H20()- Ca(OH)2(aq) OH 653.1 kJ 2CO2(g)H2O(l OH1300 C2H2(g)5/202(g) kJ C(graphite) O2(g)CO2(g) H= -393.5 kJ calculateH for the reaction (show your work for full credit) CaC2(s)+ 2H20()- Ca(OH)2(aq) CH2(g)