Question

Enter your answer in the provided box. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine A Hrxn for C(diamond) — Сgraphite) with equations from the following list: (1) C(diamond) + O2(g) + CO2(g) (2) 2 CO2(g) → 2 CO(g) + O2(8) (3) C(graphite) + O2(g) → CO2(g) (4) 2 CO(g) → C(graphite) + CO2(g) AH=-395.4 kJ AH = 566.0 kJ AH = -393.5 kJ AH=-172.5 kJ AHoverall = kJ

Answer 1

Answer! (diamond) - C graphite Cydiamond) + oz x3 cookies oH = -395.4K) Coulo) → Cgpaphate) + OLD) OH = 3.43.5 kJ lidiamore) → graphite) OH = – 395.44JT 393.5 kJ JOH= -1.9 kJ "please rate itn.