What volume of 0.355 M HCl is needed to make 200. mL of 0.150 M HCl ?
Answer
M1 = 0.355M
V1=?
M2= 0.150M
V2 = 200 mL
Using the molar equation
M1 ×V1 = M2×V2
0.355M ×V1=0.150 M×200mL
V1= 84.51mL
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