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14) A correlation for male body density, n, in [g/cm3] is given by the equation: H0.725 n 0.0277 W0.3 +0.75 where Wis mass in

if you can detail from C to E it will be really appreciated

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solution q=0.0277 40.725 12 +0.75 Giren unit n = Ilm² Ho cm W 2 kg. So unit of constant 0.0277 and 0.75 will be - the enit of(e.) modity equation na ng Im?. Ham wa kg. 6:3 il * 1,0.725 unir conversion ; na 0.0277H - +0.25 19 210 kg ti Tas ikg - looogConvert d.) height tom (Sem) 900-0277 40.35*70.15 277 HO.725 tours (on5= 31cm) :[ims 100.com] No.3 0725 og x M 0.0277 kg. + 8Thank you

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