Please help #2! Genetics !!Homework Answers
c) AbBb offspring is formed from a cross AaBb X AABB, the punnett square is as follows: -
| genotype | AB | Ab | aB | ab |
| AB | AABB | AABb | AaBB | AaBb |
| AB | AABB | AABb | AaBB | AaBb |
| AB | AABB | AABb | AaBB | AaBb |
| AB | AABB | AABb | AaBB | AaBb |
Hence, based the above, An offspring AaBb from the cross between AaBb X AABB is 1/4.
3) As the color-blind allele is linked to the X chromosome and mother is heterozygous for the allele then,
genotype of the mother would be XbX (as mother has 2X chromosome) and
genotype of the father would be XbY (as father has single X chromosome)
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Please help #2! Genetics !!
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