# of individuals with each genotype |
|||
Population |
+ / + |
+ / – |
– / – |
1 |
94 |
69 |
18 |
2 |
112 |
73 |
21 |
3 |
67 |
4 |
2 |
4 |
92 |
23 |
9 |
You are working in a laboratory that is studying the characteristics of a gene that is associated with a newly described disease. The dominant form of the gene (represented by a + in the table below) does not cause any disease, while the recessive (represented by – in the table below) does cause the disease. Heterozygotes are also unaffected. You examine several populations and gather the information in the table below. Now imagine that you are examining a second disease, but that the recessive form of the gene provides some protection against this second disease (through heterozygote advantage, perhaps). As a result, the fitness values are w11 = 0.75, w12 = 1 and w22 = 0.82 If this is true, which one of the four populations is most likely to live in an environment where that second disease is present and what leads you to that conclusion? (4 pts)
1. Answer : The population in Hardy - Weinberg equilibrium
Calculation :
In a population of mice a particular locus has two alleles A1 (dominant) and A2 (recessive)....
In a population of mice, there are two alleles of the A locus (A1 and A2). Tests showed that in this population there are 300 mice of genotype A1A1, 200 of A1A2 and 250 of A2A2. What is the frequency of the A2 allele in the population? (enter as decimal- with zero & rounded to nearest hundredth)
Question 2: In an outbreeding diploid population, an autosomal locus has two alleles, A1 and A2. You observe the allele frequencies of A1 and A2 are both equal to 0.5, and the relative fitnesses of the three genotypes (A1A1, A1A2, and A2A2) are equal to 2, 1.5, and 1, respectively. A) Which allele will become fixed in this population? (1 point) **The recessive beneficial allele A2A2 will eventually become fixed in the population (A2A2=1) B) What is the allele frequency...
(Hardy Weinberg Equation) In a population of rabbits, there are 423 A1A1, 1484 A2A2, and 1661 A1A2 individuals. If the enviornment changes so that the homozygous recessive genotype suffers a reduction of fitness where it's fitness is now 0.59 , but the other genotypes are unaffected, what will be the frequency of the dominant allele in the NEXT generation?
You are studying a population of milkweeds and you find the following allele frequencies: f(A1A1) = 0.36 f(A1A2) = 0.48 f(A2A2) = 0.16 If the fitness of the heterozygote (w12) is 0.9 and the average fitness of the population is 0.916, what do we expect the new frequency of the heterozygote genotype to be in the next generation?
At a locus (A) with two alleles (A1 and A2) in a population of leeches, you accumulate the following genotypic data: A1A1 A1A2 A2A2 total observed # 35 151 109 295 Perform a chi-square test to determine whether this population is in Hardy-Weinberg equilibrium at this locus. Be sure to show your work and in a sentence or two interpret the result of the test.
5. Examine the following fabricated data for a population of oak trees. Genotype Height Number of individuals with this genotype in generation 1 Number of individuals with this genotype in generation 2 A1A1 5 meters 100 200 A1A2 10 meters 100 A2A2 15 meters 100 200 TOTAL: 300 450 a. (2 pts) What is the allele frequency of A1 in the first generation? b. (2 pts) is this population in Hardy-Weinberg Equilibrium? Show your work.
1. Fixation of Dominant Alleles Start with a population that has a gene with two alleles (A and a) with classical Mendelian dominance that are at equal frequency (p0.5. q 0.5). Assume this first generation is at hardy Weinberg equilibrium. Calculate the genotype frequencies AA- a. Aa b. Now assume some environmental change that makes the recessive phenotype completely unfit (fitness- 0). Calculate the allele frequencies and genotype frequencies in the second generation. (Hint: Your calculations might be easier if...
Problem ***. A population of jewel beetles has a striped and plain phenotype. Two stripes is the recessive phenotype. Plain is the dominant phenotype. However, heterozygote individuals an intermediate phenotype bearing one stripe. Jewel beetles are abundant on islands. On one particular island an invasive rodent has been introduced which preferentially preys on striped beetles. In a population sof 26,760 beetles. Approximately 18,200 beetles are two striped. Calculate the genotypic and allele frequencies. If the introduced rodent consumes 70% of...
We're considering a fully recessive, deleterious (harmful) mutation (A2) at an allele frequency of q = 0.01 (one percent) in a large outbreeding population. Thus p(A1) = 0.99. 1. What is the population frequency of A2A2 homozygotes? 2. What is the population frequency of A1A2 heterozygotes? 3. Of all the A2 alleles in the population, what proportion are in heterozygotes? 4. And what proportion are in homozygotes? 5. Now, your country starts a policy of sterilizing all the affected individuals...
1. We're considering a fully recessive, deleterious (harmful) mutation (A2) at an allele frequency of q = 0.01 (one percent) in a large outbreeding population. Thus p(A1) = 0.99.1. What is the population frequency of A2A2 homozygotes? 2. What is the population frequency of A1A2 heterozygotes? 3. Of all the A2 alleles in the population, what proportion are in heterozygotes? 4. And what proportion are in homozygotes? 5. Now, your country starts a policy of sterilizing all the affected individuals...