ncetoi paper) 1. BSA stock solution A has a concentration of 3.50 mg/mL. 1.00 mL of...
4. (a) Determine the experimental concentration of protein in the unknown solution in mg/mL using the Part II Data Table and the equation on page 2 for the absorbance assay at 280 nm. Hint: Convert the molar concentration (M or moles/liter) of BSA from absorbance assay at 280 nm method to mg/mL, assume that the molecular weight of BSA = 66.5 kDa [7 points 6500 g/mol Post-lab 10 Report Form: Determination the Concentration of a Protein You must show your...
From a 2,000 μg/mL BSA stock, create 1 mL of each of the following stock solutions in 0.02 M phosphate buffer using individual microcentrifuge tubes: 50 μg/mL, 250 μg/mL, 500 μg/mL, 1,000 μg/mL, 1,250 μg/mL, 1,500 μg/mL. Calculate the volume of BSA stock that will be required to make the standard solutions needed to create the BSA standard curve. Be sure to show your work and include the volume of 0.02 M phosphate buffer required to reach a final volume...
A stock solution of bradford protein assay reagent contains 0.5 mg/ml or the reactive dye called brilliant blue G-250. to use the stock, you must first dilute it five-fold, i.e..,1/5X. what is the concentration of dye in the diluted working solution.
1) A graph of the Absorbance vs Concentration of BSA at 545 nm has a linear trendline with the equation y = 0.6587x + 0.0001. Please calculate the concentration of an unknown sample with an absorbance of 0.330. 0.0001 mg/mL 0.217 mg/mL 0.6587 mg/mL 0.501 mg/mL 2) Please review the “Absorbance Assay at 280 nm” portion of your lab. Please calculate the concentration of an unknown sample with an absorbance of 0.330, path length 1.00 cm, and a molar absorption...
1. Serial dilution Questions: a) (5 pts) Suppose you begin with stock solution of dye that has a concentration of 350.0 mg/L and do the following set of serial dilutions on it: 5.00 mL of stock diluted to a total volume (TV) of 500.00 mL (Dilution 1); 2.00 mL of Dilution 1 is then diluted to a TV of 250.00 mL (Dilution 2); finally, 1.00 mL of Dilution 2 is then diluted to a total volume of 100.00 mL. Calculate...
2.(1 point) You have 125 μLof a protein sample. Of this, you dilute30μLinto 120μLof buffer. 50μL of that dilution were used for a Bradford assay and produced an absorbance of 0.53.Using the standard curveyou built in the lab using BSA, find the protein concentration (in μg/μL) of the original protein sample. Show your work. (Hint: first find the dilution fold of the sample that was used for the assay.) Note: equation from standard curve: y=0.0093x + 0.1877 show all work.
The initial concentration of a protein sample is 25 μg/μl. Calculate the volumes of the stock protein and water (diluent) necessary to prepare a 1:5 dilution in a final volume of 4 mL. What is the diluted concentration? Volume of Protein: Volume of Water: Resulting Concentration:
Suppose 5.00 mL of a 1.00 M stock solution is diluted to 25.00 mL. Afterwards, 5.00 mL of this solution is diluted to 25.00 mL. What is the concentration of the final solution?
Please show work:
1) Complete the calculations and fill in the missing volumes needed below to create a six-tube solute dilution series from a protein stock solution, 1.0 mg/ml BSA (bovine serum albumin) into 1.5 ml microcentrifuge tubes using CIVI = C2V2, note V2 is not 1.5ml. A table is provided below to record your efforts. New solutions Tube Concentration Volumes stock protein Dl water Final volume 1.00 mg/ml 250.0 ul 0.0 ul 250.0 ul 250.0 ul 0.80 mg/ml 0.60...
Given 37ul of a 100 mg/ml stock solution of Bovine Serum Albumin (BSA), diagram the most accurate procedure so you end up with at least 500ul each of 5ug/ul, 0.5 ug/ul, and 0.05 ug/ul working solutions of BSA.