Question

Part A g e Powerper Phase Express you to the significant figures and includer e Learning Goal To calculate average and power supplied by a wye-configured source as well as the average and total power delivered to a wye-configured load A balanced three-phase wye-connected generator with positive sequence has an impedance of 0.23 +0.51 / and an internal voltage of 120 Vl. The generator feeds a balanced, three phase wye-connected load having an impedance of 42 +22 The impedance of the line connecting the generator to the load is 0.6+ 1.6 Ne Thea-phase internal voltage of the generator is specified as the reference phasor P Value Units Submit Part 1 - Total Average Power to the Load - Part Average Power Lost in the line Calculate the average power lost in the line Clouise the follwerage power delivered to the load Express your answer to three significant figures and include appropriate units View Available Hints View Available in Value Units A Value Units Sam Part - Magnetong Va Asted Pant Power Loss in the Generation Calculate the sumber magnetong was bored by the Calculate the Express your a powers in the generator i cles and include propriate units rt PROG? Valve Units HAO? Value Units Po Q-

Answer 1

Zy = 0.23 +10.571/pn Zy=42 +3322/ph Z line = 0.6+j lobs/en Van = 12020 v Phase a Circuit! = Zline > 1 lat obtilber 4 42+1 32.2/ph zg 10.23+10.57 Van o Izolov Iss line Current - 120 l A 0.23 tjo.u toobtii.b +42+132 Taa= 2.192 (-38.53A Partit! Average Power Pen phase is PA=Tan I Ica I Cos (Oran Osat ) Po = 120 x 2. 192 Cos (0+38.53) w

P6= 205.771 wl PartBi Total average Power delivered to load 12 TaAI X 42 Pr= 31 Jan ²x42 Pr=3(2.192]²x42 W Pr = 605.4130) Partc: Average Power lost in line Pline =31 Jan 1x 0.6 W Pine =3(2.192)²x0,6W Pline = 8.649 w) Parto: Total average power lost in Pgen = 31 Jan 8 x 0.232 Pren= 3(2.19 28² * 0,23 W I Pren= 3.315wl generator

load is Part El Masnerizing VAR's absorbed by Pr=3) Ian P x 32 Pr = 3 (2.192 3² x 32 VAR Pr = 461.267 VAR