Question

QUESTION: Using the volumes and concentrations given in Table 13-2 of the instructions, calculate the diluted concentration of the hydroxide ion at time zero, [OHlo, for each of the 3 solutions. You must take into account the total volume after all solutions have been added together. Show your work here and record the values on your Report Sheet in Table 13-4 as well. (Hint: CV C2V2 may be applied here). [1.0 point] 1. Solution Calculated [OH]

Answer 1

Preparation of solution rightarrow In solution '1' we added 20.00 ml of 2.00 times 10^-5 M crystal violet, 0.00 ml of water and 20.00 of 0.0200 M of NaOH (ml) It means Initial volume of [OH^-] or [NaOH]^+ is 20 ml final volume of solution = (20.00 + 0.00 + 20.00) ml = 40.00 mL Initial concentration of [OH^-] or [NaOH] = 0.0200 M Now, Apply c_1 v_1 = c_2 v_2 = > (0.0200 times 20) = (c_2 times 40.00) = > c_2 = 0.0200 times 20/40.00 = 0.0100 M Diluted concentration of [OH^-] in solution I is 0.0100 M rightarrow In solution '2' we added 20.00 mL of 2.00 times 10^-5 M crystal violet, 10.00 mL of water and 10.00 mL of 0.0200 M NaOH solution \r\n Initial volume = 10.00 mL final volume = (20.00 + 10.00 + 10.00) = 40.00 mL Initial concentration = 0.0200 M Now apply, c_1 v_1 = c_2 v_2 = > (0.0200 times 10.00)