Homework Answers
Solution: Voltage on a disharging capacitor is given as:
V = V0 e(-t/T)
Where, V0 - initial voltage , T = time constant and V - Voltage at time "t"
ATQ, V = 5%V0
=> V = 0.05*1500V = 75V
Plugging the known values in the equation,
=> 75V = 1500V e^ (-40/T)
=> 0.05 = e^ (-40/T)
=> ln(0.05) = -40/T
=> T = 13.33 ms.
We know that, T = RC
where, R is resistance and C is capacitance = 100μF (Given)
=> 13.33/100*10^-3 = 133.3 ohms. Answer
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