Question

A ball and socket at A. Cable BD at B, and a smooth surface at C support rod ABC. The smooth surface that provides the support at C lies in the yz-plane. C(0,12,6) ft D(6,0,3) ft B(6,6,3) ft 124 lb BS (12,0,0) ft Determine the reaction components that the ball and socket exert on rod ABC, the tension in cable BD, and the force the smooth wall exerts on end of rod ABC: Note that cable BD does not pass through point o. (Indicate the direction with the sign of your answer. Enter your answers in pounds.) FAXL

Answer 1

PPlA= (6-12) î+(6-0)ņ+(3-0 2-6î +69 +3ť SclA= (0400 + (12-02 + (6-0) & = -12 1 + 12 9 +6F - oê taſtoß --19 force vectors TBD ² - Bo , F = Fc W = -124 F "laking Moment about IMAO (BAXT) + BAXTO) + ( 5A X Fed=0 * Êi RT 12 Â I "1-6 63 +1-6 6 3 +/-12 12 6 120 Too-129 | To-Boo Ilfool → 9 (-744)-9 (744)+R(o)+1(0+31&o)-(0)+R (6tes) +2(0)+ -]{0-6fc) +F (0-12 Fc.) = 0 (-744+3T8D) Î +91-94476f) + f (0+6789 – 12 Fe)-0 by comparing, -744+3980 = 0 T802 248 .4b, Tos-248 -744+6 Fc=0 Fez 124.46 Fez 124 lb FC = n4 EF=o @FAxît Fay?+ FAZE) + TBD + + RC=0 & Faxê + Fay it FAZÊ + (-2489) + (-124 €) + 1242=0 =) (FAX + 1245+ (FAY - 248) } + (FA2-124) E 20 By Comparing both sides, (FAXI 124)=0, FAX=124 FAX=-124? FAY-24870; Fax=248 FAY=2489 Now e FAZ-12400 IF A2=124 FAZ=1248