Please provide all steps and a detailed explanationHomework Answers
PCl5(g)----------------->PCl3(g) + Cl2(g)
1mole of PCl5 decomposes to gives 1 mole of PCl3
208.24g of PCl5 decomposes to gives 137.33g of PCl3
127g of PCl5 deomposes to gives = 137.33*127/208.24 =83.75g of PCl3
percent yiled = actual yield*100/theoretical yield
84.8 = actual yield*100/83.75
actual yield = 84.8*83.75/100 = 71.02g of PCl3
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