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Assume that a structural engineer decides to use a normal distribution to model the strength of concrete. The mean value of c
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Answer #1

M= mean = 3 Se0 bsi Variance=83 333 psia dr= Ve3333 iP(X7 3600) = P/X 36e0-3500 V83333 = P(Z) 0.35 |-P{2<0135) =-0.6368 = 0.

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