Genes A and B are located on the same chromosome 10 centimorgans apart. What is the likelihood of AB/ab progeny in a cross between Ab/aB and ab/ab individuals?
a. 1/20
b. 1/10
c. 1/4
d. 9/20
e. 9/10

Genes A and B are located on the same chromosome 10 centimorgans apart. What is the...
Three genes are located on the same chromosome and are known to be 8 mu apart between A and B, and 12 mu apart between B and C. The heterozygous AaBbCc genotype individuals were crossed to homozygous recessive aabbcc genotype individuals (test cross) and observed 3 double crossover offsprings. If this cross produces a total of 500 offsprings, what are the expected numbers of double crossover offsprings and calculate the Interference (1) value. (3 points) 4·
2. Genes A and B are linked on the same chromosome. The recombination frequency between the two genes is r = 0.2. Given this cross between two individuals: AB/ab x aB/Ab, what is the probability of the cross giving progeny of the genotype ab/ab?
Suppose the A and B genes are on the same chromosome but separated by 100 map units. What fraction of the progeny from the cross AB/ab x ab/ab would be AB/ab?
43. Genes a and b are X-linked and are located 7 mu apart on the X chromosome of Drosophila. A female of genotype a+ b/a b+ is mated with a wild-type (a+b+/Y). a. What is the probability that one of her sons will be either a+b+ or a b+ in phenotype? b. What is the probability that one of her daughters will be a+b+ in phenotype? 44. Three recessive autosomal mutations in Drosophila: a versus wild-type A. b versus B,...
The genes for fin length and color are so far apart on the same chromosome that an excess of recombinant progeny was observed. Question 4 16.5 pts In the goldfish, the allele for dark color (C) is dominant to that for albino (c) and the allele for long fins (L) is dominant to the allele for short fins (1). A dark, long-finned goldfish is crossed to an albino, short-finned goldfish and the following phenotypes are observed in the progeny: Phenotype...
Two genes, A and B, are 64 cM apart on a chromosome. How can we measure the genetic distance between A and B? In a test cross between a double heterozygote and a homozygous recessive individual, we should observe 64% recombinant progeny If gene C lies between A and B, we can measure the recombination rate between A-C and C-B. Both of the above will work There is no way to measure genetic distance greater than 50 cM. I know...
6. The table below gives the recombination rates of genes located on the same chromosome. Genes Rate of recombination a,b 50% ac 15% ad 38% a,e 8% b,c 50% b,d 13% be 50% cd 50% ce 7% d, e 45% Draw the genetic map of this chromosome.
genes A and B are 20 map units apart. If you cross Ab/aB xab/ab, how many each progeny type would you expect if total progeny was 1000. a. AaBb(AB/ab) b. Aabb ( Ab/ab) c. aaBb(aB/ab) d. aabb(ab/ab) is b and c the parental ? would that mean that b and c are 20 ? Thanks
Which of these statements is incorrect? Syntenic genes are located on the same chromosome. Independent assortment results in recombinant chromosomes. You can reliably predict the relative genetic distance from genes’ physical distance on a chromosome. Linked genes are always syntenic. What is the relative genetic distance between two linked genes if the recombination frequency is 0.49? 0.49 cM 4.9 cM 49 cM 490 cM What statement best explains the distortion in Mendelian ratios observed by Bateson & Punnett in 1905?...
The genes A, B, and C are tightly linked to each other on the same chromosome. The genes are 2 map units away from each other. A-B=2 map units, B-C=2 map units, and A-C= 4 map units. You cross an organism that AABBCC to one that is aabbcc. You take the F1 heterozygote and cross it to aabbcc. How many offspring should you screen to observe the rare event (a double crossover progeny?) 1 – (probability of not getting rare...