Suppose the A and B genes are on the same chromosome but separated by 100 map units. What fraction of the progeny from the cross AB/ab x ab/ab would be AB/ab?
Answer:
AB/ab =25%
Explanation:
If distance between 50 map units, it means that the two genes assort independently though they are located on the same chromosome. It also means that the two genes are not linked.
AB/ab x ab/ab ---Cross
| ab | |
| AB | AB/ab - 25% |
| Ab | Ab/ab - 25% |
| aB | aB/ab - 25% |
| ab | ab/ab - 25% |
Suppose the A and B genes are on the same chromosome but separated by 100 map...
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2. Genes A and B are linked on the same chromosome. The recombination frequency between the two genes is r = 0.2. Given this cross between two individuals: AB/ab x aB/Ab, what is the probability of the cross giving progeny of the genotype ab/ab?
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Below is a map of the Drosophila melanogaster X
chromosome, giving the distances between adjacent genes in cM.
Suppose that a female is heterozygous for an inversion of the
exact entire region from v to wy.
She is also heterozygous for all the genes shown in the map, and
is test-crossed.
What percentage of her progeny will be recombinants between the
following gene pairs?
a) wy and g ___________
b) v and g _____________
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