Question

10) In a certain A-connected balanced load, the line voltages are 230 V and the impedances are 60 35 2. Determine the magnitude of the phase currents A) 1.63 A B) 2.78 A C) 3.83 A D) 4.15 A 11) In a certain Δ-connected balanced load, with line voltages of 230 V and impedances of 60 L35Ώ, determine the total power A) 920.2 W B) 2346.3 W C) 1572.9 w D) 1250.9 W 12) For a three-phase, four-wire, Y-connected load that is unbalanced, the neutral current is: A) equal to the largest phase current minus the other two phase currents. B) equal to the sum of the phase currents. C) in phase with the smallest phase current. D) zero

help find those answers please

Answer 1

v_l = 230v z_delta = 60 angle 35 I_ph = 230/60 angle 35 = 3.83 angle -35A phase current I_ph = 383 angle -35A option c I_l = squareroot 3 I_ph angle theta - 30 = squareroot 3 (3.83) angle -35 - 30 I_l = 6.63 angle -65 A power factor cos phi = cos(35) = 0.8191 total power = squareroot 3 v_l I_l cos phi = squareroot 3 (230) (6.63) cos(35) = 2163.54w total power = 2346.3 (approximately) if the system has four wires neutral current I_N = I_= r + I_Y + I_B = 0[balanced] notequalto [unbalanced] line voltage = (vph) (squareroot 3) = (100) (squareroot 3) = 173.2 v \r\n I_ph = I_l = I_load phase current line current & load current are all equal & in phase [because they are series currents] delta - delta (source-load) load voltage& line are all equal for a given phase because they are parallel