Question

2.50 g of a pure sample of a carbonate of manganese produces 0.5367 g of CO2 during complete thermal decomposition. What is t

QUESTION 2 [7 A cadmium nitrate solution is prepared by dissolving 120.0 g pure cadmium(II) nitrate in enough distilled water

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Answer #1

The structure of the carbonated Mn is the MnCO3

Now oxygen hase oxidation no. is -2 and C oxidation no. is +4

So

Oxidation state of the Mn + Oxidation state of the C + 3 * Oxidation state of the O = 0

Oxidation state of the Mn + 4 - 3(2) = 0

Oxidation state of the Mn + 4-6 = 0

Oxidation state of the Mn = 2

So oxydation state of Mn is +2 in the sampel

After thremal decompostion

2 MnCO3 (s) + O2 (g) --------> 2 MnO2 (s) +2CO2 (g)

In the Product, it is

Oxidation state of the Mn +2 * Oxidation state of the O = 0

Oxidation state of the Mn +2*(-2) = 0

Oxidation state of the Mn = 4

So in product after thermal decompositon oxydation of Mn is +4

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