Question

The physics students wish to test the law of conservation of angular momentum
perform a completely inelastic collision between two discs. They attach disc 1 (from part 1) to the rotational sensor then give it a spin. After about 4 seconds, they drop disc 2 on top of disc 1. The whole process takes only ~10 seconds total.

Use the rate of change of the single disc angular velocity and the duration of the collision to find a corrected value of initial angular velocity (?′i) at the same instant we measure ?f. Calculate the angular momentum using ?′i and compare it with the final angular momentum. Does your result improve?

Rate of change of single disc angular velocity = -1.140 rad/s/s

Masses and diameter of the discs:

?1 = (0.1064 ± 0.0005) kg

?2 = (0.1062 ± 0.0005) kg

?1 = ?2 = (89.10 ± 0.05) mm

Moment of inertia single disk = 0.0001117 kgm^2

Moment of inertia double disk = 0.0002263 kgm^2

Angular velocities:

right before collision (or initial) = 37.43 rad/s

right after collision (or final) = 18.36 rad/s

Answer 1

* (37.43rod's ) - 0.0002263 cogmy of Since there is no external torque on the system of disks angular momentum conserved. Isingle we Idouble Wf SO is = wofr 0.oool117 legm² x 37.43 radis 18.475 rad's 0.0002263 kgm2 Wf- 18.475 reed's (6 feeperiment 18-36radls wf-(Wof experimental 18-475 radis 18.36 radls= 0.115radls Scanned with CamScanner