
Q = CV
V = Q/C = 25µ/15µ = 1.67 V initial
final, V = 10/15 = 0.67 V
voltage on a cap, discharging
V = V0exp(–t/?)
RC = ? = time constant
? = 15µ x 1.0k = 15 ms
V = V0exp(–t/?)
0.67 = 1.67exp(–t/15m)
exp(–t/15m) = 0.401
–t/15m = -0.9133
t = (15ms)(0.9133) = 13.69 ms =0.0137 s
Plz solve this, I tried so many times i kept getting 0
or 6.5 and they were wrong, thank u in advance, rating will follow
for sure!
Two small metallic spheres, each of mass m-0.25 g, are suspended as pendulums by light strings from a common point as shown in the figure below. The spheres are given the same electric charge, and it is found that they come to equilibrium when each string is at an angle f 6 3.5...
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The equilibrium constant for the chemical equation N2(g)+3H2(g)2NH3(g) s Kp = 4.46 at 197 degree C. Calculate the value of the K for the reaction at 197 degree C. Kc =
kept getting 20370 but that
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I have tried this 10 times,
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(1 point) Evaluate the limit lim V x2 + 4x + 5 – x x
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fix the erorrs. tried entering the answers couple of times but
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The volume and pressure of a gas are 3.30 m3 and 2.10 atm, respectively. a) If this gas expands to twice its initial volume while the pressure is constant, determine the work done on the gas 702009 What is the difference between work done on the gas and work done by the gas? Check units for...
i
keep getting this wrong but i dont know why, i tried other
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My 2.2/6 points Previous Answers PSE6 23.P.013. What are the magnitude and direction of the electric field that will balance the weight of the following? (a) an electron (5.58 The response you submitted has the wrong sign. N/C) downward (b) a proton (1.0245 Your response differs significantly from the correct answer. Rework your solution from...
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