Question

3. A Newtonian fluid with a dynamic or absolute viscosity of 0.38 Ns/m” and a Density of 910 kg/m flows through a 25 mm diameter pipe with a velocity of 2.6 m/s. Find out Reynolds number of the fluid. Is the fluid flow lamina, transient, or turbulent?

Answer 1

Hi,

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Given that,

Absolute viscosity of the fluid, $\mu=0.38\;Ns/m^{2}$

Density of the fluid, $\rho=910\;kg/m^{3}$

Diameter of the pipe, $d=25\;mm=2.5\times10^{-2}\;m$

Velocity of fluid, $V=2.6\;m/s$

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Therefore, Reynolds number of the fluid is given by,

$R_{e}=\frac{\rho.V.d}{\mu}=\frac{910\;kg/m^{3}\times 2.6\;m/s\times2.5\times10^{-2}\;m}{0.38\;Ns/m^{2}}$

$\mathbf{\therefore R_{e}=155.66\approx 156}$

We know that, When the value of $R_{e}$ is less than 2100, then the flow will be laminar.

Therefore, this flow is laminar.

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Answer 2

Kindly tell me the name of book from which this Question has been takken??