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A defibrillator with a 910 V battery charges a 260 uF capacitor through an 845 ohms...

A defibrillator with a 910 V battery charges a 260 uF capacitor through an 845 ohms resistor. How long does it take for the capacitor to charge to 770 V?
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Answer #1

V = Vo(e^-t/RC)

770 = 910 (e^-t/(845*260*10^-6)

t = 0.036 s

so the time taken = 0.036s

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