A bar of mass M=2kg and length of .8 meters rotates about one of its endpoints with a constant angular velocity 88 rad/s
a) what is the kinetic energy of the system
b) what is the speed of the tip (given I=1/3 ML^2)
Here,
M = 2 Kg
L = 0.80 m
w = 88 rad/s
a) moment of inertia , I = 1/3 ML^2
kinetic energy of the system = 0.50 * I * w^2
kinetic energy of the system = 0.50 * 1/3 ML^2 * w^2
kinetic energy of the system = 0.50/3 * 2 * 0.80^2 * 88^2
kinetic energy of the system = 1652 J
b)
speed of the tip = L * w
speed of the tip = 88 * 0.80 m/s
speed of the tip = 70.4 m/s
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