In Java for [computing] please. Thanks.
Implement a method public static double[] difference(double[] vec1, double[] vec2) to compute the (component-wise) difference of vectors vec1 and vec2 as a new vector. Assume that vec1 and vec2 are of the same length. The difference of vectors (a1, a2, . . . , an) and (b1, b2, . . . , bn) is (a1 − b1, a2 − b2, . . . , an − bn). For example, the difference of (−2, −4, 9) and (3, −2, 4) is (−2 − 3, −4 − (−2), 9 − 4) = (−5, −2, 5). (7 marks)
Main.java
public class Main
{
public static double[] difference(double[] vec1,
double[] vec2){
int l = vec1.length;
double[] diff_vec = new double[l];
for(int i=0; i<l; i++)
diff_vec[i] = vec1[i] - vec2[i];
return diff_vec;
}
public static void main(String[] args) {
double[] vec1 = {-2, -4, 9};
double[] vec2 = {3, -2, 4};
double[] diff_vec = difference(vec1, vec2);
System.out.print("Difference vector: ");
for(int i=0; i<diff_vec.length; i++)
System.out.print(diff_vec[i] + "
");
}
}
In Java for [computing] please. Thanks. Implement a method public static double[] difference(double[] vec1, double[] vec2)...
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public class CheckBST {
//method to implement
public static boolean isValidBST(TreeNode root) {
}
public static void main(String[] args) {
TreeNode a = new TreeNode(1);
TreeNode b = new TreeNode(2);
TreeNode c = new TreeNode(3);
a.left = b;
a.right = c;
System.out.println(isValidBST(a));
TreeNode d = new TreeNode(2);
TreeNode e = new TreeNode(1);
TreeNode f = new TreeNode(3);
d.left = e;
d.right = f;
System.out.println(isValidBST(d));
}
}
TreeNode.java
class TreeNode {
int val;
TreeNode left;
TreeNode...
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