Question

Air 2 bar Petroleum 2,5 m T10cm

Question 8

At the bottom of a pressurized petroleum tank there is a 10 cm diameter hole through which petroleum is poured into the atmosphere. Water level is 2.5m higher than the hole.

(Friction losses will be neglected.)

1)Calculate the initial flow of water discharged from the tank.

2)What is the height of the petroleum after 10 seconds?

Density of petroleum = 850 kg/m³

Base diameter = 70 cm

Atmospheric pressure = 101325 Pa

Air pressure on the water surface = 2 bar (effective)

Answer 1

Born Drawing the Given figure and the data, worting 0.7m Parm - 101325 Pa X Air 12 bar ) 1 Petroleum dh 1 2.5 m = 7, .850 Dafunt, d loom - 12 God 2 1) ) Applying Ber nauli's equahon blus point Vi ? P P2 +Z V₂² to log ag og 29 is zelo . at interface Assuming vedouty Vo =0 2 101325 V2 + (2+1)x101325 850 X 9.81 + D + 2.5 850x9.81 2x 9.81 Vaz 22.93 mts How initial flow rate from the tank. Q: + (903) 10.1)? * 22-934 Q: 0-18 m/s Vz

After t , second it's height falls to 'h'm. aben abando availaible at point, sy net head hoet hafrukum + hipremus of air ht 2x10325 85009:47 hy hnet h +24.3029 Sinu. the this is case of emptying of tank Diniet - Dowiet Ostorage - Canotaghnt Atank dh at no loss at ew't is given . Gas dh !1 'Cd to 29 dt Arank Whet - dh 1x4x0.1? x Vox3.8) dt A x 0.72 ht24.30 both sides. Integerating h I 2.5m t=0 2. m t=10s h h -db tve as 10 h is fiml dt = ) 0-09 th +27.30 limit. 2.5

& 12.5 70.09(10-0) - + 2 ( th +24:30 0.9 11 2 2 (52-5424.30 √6 +24.30 h +24.30 22:39 ñ h -1.956 m Ans. T * Here -ve indicates that height ht is degree geasing

Please forgive me for any calculation mistake and do comment for any short of queries.