Question

A resistor with RRR = 300 ΩΩ and an inductor are connected in series across an ac source that has voltage amplitude 510 VV . The rate at which electrical energy is dissipated in the resistor is 276 WW . Figure of 0

Part A Part complete What is the impedance ZZ of the circuit? Express your answer with the appropriate units. -- SubmitPrevious AnswersRequest Answer Part B Part complete What is the amplitude of the voltage across the inductor? Express your answer to two significant figures and include the appropriate units. -- ZZ = nothing nothing SubmitPrevious AnswersRequest Answer Part C Part complete What is the power factor? Express your answer to two significant figures and include the appropriate units. -- VLVL = nothing nothing cosϕcos⁡ϕ = nothing

Answer 1

at resistor P= power dissipated I 2 R 276 Part A I= 0.96 A Vo= IoZ. Impudance za Von = 5:06 [2=531.70 m Part Bit Voltage amplituce across the resistance VR IR VR0.96 X 300 Tv - 287.8 volts Now: (510)2 (28718)? + V2 voltage amplitude v = √ (570)2 _ (287. 82 ķ=421 volts Partei power factor = B = $207, = 0.564 power factor =0.564 / accross the cade