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4. Determine the product of the following epoxide reaction in acidic conditions: CH3OH H2SO4 (trace) please show mechanism arrows with steps
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Answer #1

The product of the given epoxide reaction in acidic conditions is to be determined.

CH, OH H,SO(trace)

Epoxides are cyclic ethers which have a lot of ring strain, so opening of epoxide is very common reaction when epoxide undergoes solvolysis.

When epoxides are reacted with methanol in slightly acidic medium, then ring opening occurs by SN1 mechanism and the nucleophilic attack occurs at more substituted carbon atom.

It occurs in two steps-

Oxygen atom of epoxide is protonated to turn it into a good leaving group.

Then nucleophile attacks at the most substituted carbon.

HVA нсан Step 1 Н. Суннсон с с -c-С Н Step 2 3 НАС нес- Nuc Nuc нска Н.с.сся H Backside attack at more substituted carbon

Thus, for the given reaction, nucleophile is CH3O- and acid is H2SO4.

— он CH,OH H2SO4 (trace) O-CH More substituted carbon Product

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