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Set P1 = 8 kN and P2 = 11 kN .

Determine the force in member AB,AF,BC,BF,CD,CE,DE,EF,and FG and state if the member is in tension or compression.

OK - 2m - -1 m

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Answer #1

Given- P = 8KN P2 = 11KN C 11 Ô Ồ. P2 P2 P 2m im 2m kim 0= tan ( ) = 63:435° ta tan (2) = 45° B = tan 6 = 26.56 osº consideConsider point E. Efy=0 -Xcosu5 12.298 x cos (26.56505)=0 RBE = -15.556 KN COREEA A 26.56505 RDE Efn=0 RCE=0 RBE -REE X+ 15.5Ans:- KN Force in members – AB=-16.4995 cc). AF = -21.242 KNCC) BC= -5.4998 KNCO) BF= 18.9997 KNCT) CD= -5.4998 KN CC) EF = 1

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