
QUESTION 6 The DNA sense (coding) strand for a particular amino acid is 5'-CAT-3'. What RNA...
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Question 10 If a codon on mRNA IS UGC what will be the anticodon on tRNA and which amino acid will it make? AAA., methionine ACG, cystein UUU, phenylalanine AUG, methionine © UAC, tyrosine
B) If this mRNA is translated beginning with the
first AUG codon in its sequence, what is the N-terminal
amino acid sequence of the protein that it encodes?
can you help me solve A and B
The 5'-end of an mRNA has the sequence: ...GUCCCAUUGAUGCAUGAAUCAUAUGGCAGAGCCCGCUGG... a What is the nucleotide sequence of the DNA template strand from which it was transcribed? The Standard Genetic Code AAA Lysine CAA Glutamine GAA Glutamate UAA stop AAC Asparagine CAC | Histidine GAC Aspartate UAC...
Translation: find the start codon AUG on the mRNA below, underline nucleotides in sets of three (codons), find the appropriate amino acid for each codon in the chart below, and stop when you come to a stop codon. Translate the following mRNA. AACACCAUGACCUACAUAGGGAGGGACUUAGUAGCGGAGGGGUGAUCAUUA The genetic code UUU phenylalanine UCU serine UAU tyrosine UGU cysteine UUC phenylalanine UCC serine UAC tyrosine UGC cysteine UUA leucine UCA serine UAA STOP UGA STOP UUG leucine UCG serine UAG STOP UGG tryptophan CUU leucine...
Use the genetic code table to answer the following question: Second Base First Base Third Base UUU UUC Phenylalanine U UCU UAC UCA UCG Serine UUA UUG Leucine UAU UGU UAC Tyrosine UGC Cysteine UAA Stop codon UGA Stop codon UAG Stop codon UGG Tryptophan CAU CGU Histidine CAC CGC Arginine CAG Glutamine CGG CUU CUC CUA CUG Leucine CCU CCC CCA CCG Proline CAA CGA AUU AAU Asparagine AGU Serine AGC AUC AUA Isolaucine ACU ACC ACA ACG AAC...
Repo Fill in the needed bases, codon, anticodon, or amino acid needed to complete the following table that relates the sequences of DNA, mRNA, RNA, and the resulting polypeptide. DNA informational strand: 5' end 3' end Guide DNA template strand: 3' end GTC CCC GCG GGG ACG TTG 5' end mRNA codons: 5' end 5' end 0 0 3'end 3' end tRNA anticodons: Polypeptide: TABLE 22.3 The Genetic Code - Triplets in Messenger RNA First Base (5 end) Second Base...
Question 24 Refer to the table below to answer the following question. А G U Serine Serine Serine U с A UAA U с А с w Phenylalanine UCU UUC Phenylalanine UCC UUA Leucine UCA UUG Leucine UCG CUU Leucine CCU CUC Leucine сос CUA Leucine CCA CUG Leucine CCG Isoleucine ACU AUC Isoleucine ACC AUA Isoleucine ACA AUG Methionine Start ACG GUU Valine GCU GUC Valine GCC GUA Valine GCA GUG Valine GCG UAU Tyrosine UAC Tyrosine Stop UAG...
6:35 5 minutes ago 25) Which of the following turns off transcription by binding to the operator? A) repressons B) lactose C) RNA polymerase D) promoters E) enzymes 25) 26) In bacteria, what name is given to a cluster of genes with related functions, along with their control 26) A) exon B) operon C) promoter D) activator E) regulatory gene A mutant bacterial cell has a defective aminoacyl synthetase that attaches a lysine to tRNAs with the anticodon AAA instead...
Question 9:
The genetic code is read in groups of three nucleotides, called
codons, in mRNA that specifies for a particular amino acid.
tRNA molecules act as the amino acid carriers that by correctly
pairing with the codon on mRNA can deliver the correct amino acid
to the ribosome during translation. At the tip of each tRNA
molecule is a group of three nucleotides called an anticodon and at
the other end is where the corresponding amino acid is attached...
QUESTION 34 The gene encoding an E. coli tRNA containing the anticodon 5'-GUA-3' mutates so that the anticodon now is 5'-UUA-3'. What will be the effect of this mutation? a. The bacterial ribosomes would stop translation whenever a tyrosine codon in a mRNA is positioned in the A site. b. The bacterial ribosomes would stop translation whenever a leucine codon in a mRNA is positioned in the A site. c. The bacterial ribosomes would compete with the termination factor to...
Student Sheet Name Title: Making Sentences of DNA structions coded in DNA in this activity yoids. The words Introduction: The instructions coded in DNA must be read and turned into pro molecules for the cell to carry out the instructions. In this activity you will model this process using sentences for DNA and RNA and words for amino acids. The words must line up in the correct order for the protein to form properly, just like words in a sentence...