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Using the superposition principle, find the steady state current i(t) for the circuit shown. vs(t) = 10 cos 10t V, is = 3A. 5
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I= – is x 10 = -3X lo 15 10+5 i = 1 cos (lot - 17 ict) = 1,CH) + I -T cos (lot - - 2 <3consider source lo coslot 10 Coslot 10 Loo ; W = 10 rad/sec L = 1.54 X = wh = 10x1.5 = 152 x = wc 10x loxlo - los M 5 m2 ј5 -

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