Question

All elect lie healer has the resistance R = 10ohm. Two identical electric heaters are connected in series, and then connected to the electrical source with potential difference AV = 115 1V. Calculate the total electric power consumed by the two heaters "in-series". Two identical electric heaters are connected in parallel, and then connected to the electrical source with potential difference delta V = 115 Calculate the total electric power consumed by the two heaters "in-parallel". Answer, how the two heaters must be connected in order to generate the maximum heat, in series or parallel.

Answer 1

a) When they are connected in series the equivalent resistance is:

a) When they are connected in series the equivalent resistance is: R_eq = 2R then the electric power consumed is: P_series = V^2/R_eq = 115^2/2(10) = 661.25 W b) When they are connected in parallel the equivalent resistance is: R_eq = 1/1/R + 1/R = R/2 then the power consumed is: P_parallel = V^2/R_eq = 115^2/5 = 2645W c) To get the maximum heat they must be connected in parallel.

then the electric power consumed is:

b) When they are connected in parallel the equivalent resistance is:

$R_{eq} = \frac{1}{\frac{1}{R}+\frac{1}{R}} = \frac{R}{2}$

then the power consumed is:

c) To get the maximum heat they must be conncted in parallel.