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due al 12 This is a graded discussion: 25 points possible Discussion: Hypothesis Testing Hypothesis originates from the Greek
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Answer #1

Let's take a case:

Mr. X does exercise daily for a average of 60 minutes daily with standard deviation of 10 minutes.

Here is the data for last 10 days

Day Exercise duration
1 65
2 68
3 54
4 58
5 61
6 59
7 64
8 57
9 64
10 68

The seven step hypothesis is as follows:

1. Assumptions:

a. The data values are randomly selected

b. The data is normally distributed

2. Null Hypothesis

Ho: The mean value is equal to 60 minutes

3. Alternate Hypothesis

Ha: The mean value is not equal to 60 minutes

4. Acceptance Criteria

The level of significance (acceptance criteria) is assumed to be 0.05

5. Test

one sample t test will be used.

Following is the formula:

X-u t= o Jn where, X = Sample mean u = Population mean o = Standard Deviation n= Sample size

The sample mean and standard deviation can be easily calculated in excel:

Following are the steps to calculate the mean and standard deviation:

Step 1: Put the data onto the spreadsheet

Day Exercise duration 11 65 68 N 3 54 4 58 Ол 61 6 59 7 641 8 571 64 9 10 68

Step 2: Determine the mean using (=average) command

Day Exercise duration 1 65 2 68 3 54 4 58 5 61 6 59 7 64 00 57 9 64 10 68 |=AVERAGE(C3:012)

Day Exercise duration 1 65 20 681 3 54 4 58 5 61 6 59 7 64 8 57 9 64 10 68 Mean 61.8

Step 3: The standard deviation can be determined using the (=stdev.s) formula:

Day Exercise duration 65 68 1 2 3 54 4 58 5 61 6 59 7 64 8 57 9 64 10 68 Mean 61.8 Standard Deviation STDEV.S(C3:012)

Day Exercise duration 1 65 68 N 3 54 4 58 5 61 6 59 64 7 8 57 9 64 10 68 Mean 61.8 Standard Deviation 4.756282

By putting the above values in the given formula we get:

61.8-60 t=. 4.756 = 1.196 /10

degrees of freedom = n -1 = 10 -1 = 1

6. Evaluate results;

By referring to the t-distribution table for two tail, the p-value at t = 1.196 and df = 9 is 0.262

Since the p-value (0.262) is more than the level of significance (0.05), we accept the null hypothesis

7. Conclusion

The test results indicate the average exercise of Mr. X is 60 minutes only.

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