Question

c++

Implement the following function: 1) Name: ProcessLine a. Parameters: Int 10 character array line, charc b. Job: The function will modify line such that every occurrence of c is replaced by a "*". It will also return the count of c in line. The main() function is provided. You only need to implement the function Processline. #include <iostream> #include <string> using namespace std; int main() char line 200), c; int Count; { cout<<"Enter some text: "; cin.get(line, 200); cout<<"Enter a character: "; sin>>c; Count = ProcessLine(line, c); soutstandi cout<<"Count of "<<<<<" = "<<Count<<endl; cout<<"Modified line = "<<line<<endl; return; > Sample Input/Output Enter some text: Please go to sleep. Enter a character: e Count of e = 4 Modified line - Pl*as* go to sl**p. Enter some text: Programming is so much fun. Enter a character: m Count of m = 3 Modified line - Progra**ing is so *uch fun. US)

Answer 1

#include <iostream>
#include <string>

using namespace std;
int ProcessLine(char line[],char c);
int main()
{
char line[200], c;
int Count;
  
cout<<"Enter some text: ";
cin.get(line, 200);
  
cout<<"Enter a character: ";
cin>>c;
  
Count = ProcessLine(line, c);
  
cout<<endl;
  
cout<<"Count of "<<c<<" = "<<Count<<endl;
cout<<"Modified line = "<<line<<endl;

return 0;
}

int ProcessLine(char line[], char c) {
int count=0;
for(int i = 0; i < sizeof(line)/sizeof(line[0]); i++) {
if(line[i]==c){
line[i]='*';
count++;
}
}
return count;
}